Turn a full name into its initials, however the spaces fall.
What to build
A program that reads a full name and prints its initials and its number of words.
Requirements
- Read the whole line with
getline. - Find where each word starts, even when there are extra spaces.
- Print the initials as capital letters, then the number of words.
Input
One line with a name of one or more words, made of letters and spaces.
Output
The initials with no spaces, a space, and the number of words.
Constraints
The line has 1 to 200 characters and at least one letter.
Example
Input:
Nadia Rahman
Output:
NR 2
Why it works
A word begins exactly where a letter follows a space or the start of the line, so counting those positions counts the words, however many spaces lie between them.
Examples
Example 1 · Input
Nadia Rahman
Expected output
NR 2
Example 2 · Input
sheikh mohammad abdul karim
Expected output
SMAK 4
Hints
Hint 1
Read the whole line with `getline(cin, line)`, because a name has spaces in it.
Hint 2
A word starts at a letter that is either the first character or comes straight after a space.
Hint 3
`toupper` turns a letter into a capital. Print it as a `char`.
Solution
Show one correct solution (try it yourself first)
#include <iostream>
#include <string>
#include <cctype>
using namespace std;
int main() {
string line;
getline(cin, line);
string initials = "";
int words = 0;
for (size_t i = 0; i < line.length(); i++) {
if (line[i] != ' ' && (i == 0 || line[i - 1] == ' ')) {
initials += (char)toupper(line[i]);
words++;
}
}
cout << initials << " " << words << endl;
return 0;
}